Notes on Lewin Ch3: Self-adjointness Criteria: Rellich, Kato and Friedrichs
Rellich–Kato
- Let be a self-adjoint operator and . We say that an operator defined on is -bounded with relative bound if there exists such that
- is infinitesimally -bounded if it is A bounded with relative bound for all .
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Theorem (Rellich–Kato) Suppose that is -bounded with relative bound . Then is self-adjoint on .
Moreover, if is a dense subspace such that , then we also have , i.e. is essentially self-adjoint.
Finally, if for some , then .
- in the above theorem is called the core of the operator .
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Proof uses the identity
and then exploits to get invertibility of for large enough .
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Theorem Let where
Then is infinitesimally -bounded, and
- As a corollary, we have that is self-adjoint on with spectrum that is bounded below.
Friedrichs
Let be a sesquilinear form on a dense domain . Let denote the associated real-valued quadratic form.
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Definition (Coercivity and Closure) We say an are bounded from below, or semi-bounded, if there is an such that .
If we can take , we say and are coercive.
We say that and are closed if they are coercive and is a Hilbert space.
We say that and are closable in when they admit a closed extension, in which case there is a minimal closed extension which we denote and call the closure.
- Lemma Let be a coercive sesquilinear form on . Then is closable iff for any Cauchy sequence satisfying in addition in , we have .
Symmetric Operators
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Let be a symmetric operator. The quadratic form associated with is the form
The associated sesquilinear form is .
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A symmetric operator is bounded from below/semi-bounded, or coercive, if the associated form is, and in which case we will write .
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Theorem Let be a coercive symmetric operator. Then is closable to a form defined on
Furthermore, we have
- is dense in with respect to the norm
- is dense in
- For all and all ,
- the embedding is continuous, i.e. for all .
- If is closed, then the embedding is also continuous, i.e. for all ,
If is only bounded below we can apply the above with to get a closed form.
Self-adjoint Operators
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Theorem Let and let be the associated closed form defined in the previous Theorem. For any , the following are equivalent:
- and for all .
- and .
In particular we can reconstruct from the closure of its quadratic form.
- The equation is the weak formulation of the equation . It is “weak” because we only suppose that belongs to . is the subset
- As a self-adjoint operator is fully characterized by the closure , we will abusively write , .
Friedrichs Realisation
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Theorem 3.14 showed that every semi-bounded self-adjoint operator is given by a closed quadratic form. Below we show that every closed quadratic form that is bounded below is given by a self-adjoint operator.
- this allows us to define the Friedrichs extension of any bounded below symmetric operator : from compute . Since it is bounded below, we can close it. Then the Theorem gives us a self-adjoint operator that extends .
- Theorem Let be Hilbert spaces such that is dense and continuously embedded in . Then there is a unique self-adjoint operator on , with
such that , and .
Moreover, if is a self-adjoint operator on such that is dense on and on , then .
Theorem (Kato-Lions-Milgram-Nelson) Let be a coercive self-adjoint operator and let be its associated closed quadratic form with domain . Let be another quadratic form on such that for some , and for all ,
Then is closed and coercive on , and hence it is associated with a unique self-adjoint operator , with .
If in particular is the quadratic form of a symmetric operator defined on , then is the unique self-adjoint extension of defined on , such that .
Theres more on specific examples and exercises which I didn’t get to.